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Falling Galaxies in a finite Universe is correct !
Submitted by Anonymous on Sun, 2008-05-25 20:35.
The power of this finite universe is P=c^5/G= 3645E49 watts!
The redshift is an indicator of equilibrium not expansion. The universe is in dynamic equilibrium due to conservation of gravitational energy. The math simplified is
Gravitational Energy E=-mu/R + mcv. Newton and Einstein left out the "mcv" kinetic energy. This kinetic energy is responsible for "dark energy".
Conservation of energy gives: mu/R^2= mcDel.v= mcV/R cos(v). The CentriPetal (center seeking ) acceleratin is v^2/R and the CentriFugal (center fleeing) acceleration is mcV/R cos(v).
At equilibrium mv^2/R= mvc/R cos(v) give cos(v)=v/c=z!
z is the redshift, derived from the equilibrium condition. Hubble viewed the redshift as "an unknown principle of nature". Unfortunately, the redshift measurements have been mis-intepreted as expansion. The redshift is the indicator of dynamic equilibrium, the balance of forces. Gravity creates the velocity and as such the centrifugal force. In a way gravity is responsible for the the dark energy also. v=Sqrt(GM/R) the larger the gravity the larger v and the larger mcv. The redshift is cos(v)= v/c=sqrt(Gm/Rc^2). the angle of the cosine is a measure of redshift. Cos(v) is teh beta of Relativity Theory and Lorentz's Factor is 1/sin(v)=1/sqrt(1-(v/c)^2)= 1/sqrt(sin(v)^2)= 1/sin(v).
At the boundary of the Universe, v=c z=v/c=1=cos(v) and the velocity is all radial. The Universe Radius R=158E24 meters. Hubble's constant = c/R = 3E8/158E24= 1.8987E-18= 58.48 km/s/MPc.
The age (cycle) of the Universe is 16.69 Billion years. The shape of the Universe is cuboctahedron and the density is 22E-27 kg/m^3. This density is consistent with a closed universe.
The falling galaxies is correct. The Universe is Finite and closed. The redshift is mis-interpreted by physicists.
See my book:

