# SUM OF EACH DIGIT REMAINS “9”(PIYUSH CONSTANT)

SUM OF EACH DIGIT REMAINS SAME(9),NINE
I AM VERY MUCH FOND OF MATHS ,WHATEVER I AM WRITING HERE IS AMAZING,INTERESTING,LEARN IT,VERY SIMPLE.(FOR ANY NO OF DIGITS)
NOW,I HAVE 25 AND 32, MULTIPLE THEM ,NOW YOU CAN MULTIPLE THEM IN FOUR WAYS LIKE THAT(just changing the position)
25*32=800
52*32=1664
25*23=575
52*23=1196
now substract any bigger to any lower you will always get sum of each digit nine.
1664-1196=468(4+6+8=18=1+8=9)
1664-800=864(8+6+4+18=1+8+=9)
1664-575=1089(1+0+8+9=18=1+8=9)
1196-800=396(3+9+6=18=1+8=9)
1196-575=621(6+2+1=9)
800-575=225(2+2+5=9).
this i called “piyush contant”
with lot of regards
www.piyush-g.741.com
pkgdwala@rediffmail.com
in the next topic”what all GODS HAVE COMMON”.

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### 3 thoughts on “SUM OF EACH DIGIT REMAINS “9”(PIYUSH CONSTANT)”

1. The product of multiplication of 9 follows this pattern of 9 lines of the sum of the product equaling 9 then the sum of product the tenth line equals 18 1+8=9.

9+9=18 1+8=9
9+9+9=27 2+7=9
9+9+9+9=36 3+6=9
9+9+9+9+9=45 4+5=9
9+9+9+9+9+9=54 5+4=9
9+9+9+9+9+9+9=63 6+3=9
9+9+9+9+9+9+9+9=72 7+2=9
9+9+9+9+9+9+9+9+9=81 8+1=9
9+9+9+9+9+9+9+9=9+9=90 9+0=9
9+9+9+9+9+9+9+9+9+9+9=99 9+9=18
1+8=9
9+9+9=9+9+9+9=9=9+9+9+9=108 1+0+8=9
9+9+9+9+9+9+9+9+9+9+9+9+9=117 1+1+7=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9=126 1+2+6=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=135 1+3+5=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=144 1+4+4=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=153 1+5+3=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=162 1+6+2=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=171 1+7+1=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=180 1+8+0=9
9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9+9=189 1+8+9=18
1+8=9

2. What are you writing such gibberish? And why DO YOU WRITE IN ALL CAPS?

3. Good question.